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10-2. Parabola, Ellipse, Hyperbola
medium
If $e$ and $e’$ are the eccentricities of the ellipse $5{x^2} + 9{y^2} = 45$ and the hyperbola $5{x^2} - 4{y^2} = 45$ respectively, then $ee' = $
A
$9$
B
$4$
C
$5$
D
$1$
Solution
(d) Clearly $e = \frac{2}{3}$ and $e' = \frac{3}{2}$,
$\therefore $ $ee'\, = 1.$
Standard 11
Mathematics