Gujarati
10-2. Parabola, Ellipse, Hyperbola
medium

If $e$ and $e’$ are the eccentricities of the ellipse $5{x^2} + 9{y^2} = 45$ and the hyperbola $5{x^2} - 4{y^2} = 45$ respectively, then $ee' = $

A

$9$

B

$4$

C

$5$

D

$1$

Solution

(d) Clearly $e = \frac{2}{3}$ and $e' =  \frac{3}{2}$,

$\therefore $ $ee'\, = 1.$

Standard 11
Mathematics

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