Two dice are thrown together. probability that sum of two numbers will be a multiple of 4 is

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14.Probability

easy

Two dice are thrown together. The probability that sum of the two numbers will be a multiple of $4$ is

A

$\frac{1}{9}$

B

$\frac{1}{3}$

C

$\frac{1}{4}$

D

$\frac{5}{9}$

Solution

(c) $S = \{ (3,\,1),\,(2,\,2),\,(1,\,3),\,(6,\,2),\,(5,\,3),\,(4,\,4),\,$

$(3,\,5),\,(2,\,6),\,(6,\,6)\} $

Hence required probability $ = \frac{9}{{36}} = \frac{1}{4}.$

Standard 11

Mathematics

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