Two dice are thrown together. The probability | vedclass

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Question

(c) $S = \{ (3,\,1),\,(2,\,2),\,(1,\,3),\,(6,\,2),\,(5,\,3),\,(4,\,4),\,$

$(3,\,5),\,(2,\,6),\,(6,\,6)\} $

Hence required probability $ = \frac{

Vedclass · Accepted Answer

$\frac{1}{4}$

Vedclass · Answer

(c) $S = \{ (3,\,1),\,(2,\,2),\,(1,\,3),\,(6,\,2),\,(5,\,3),\,(4,\,4),\,$

$(3,\,5),\,(2,\,6),\,(6,\,6)\} $

Hence required probability $ = \frac{9}{{36}} = \frac{1}{4}.$

Two dice are thrown together. The probability that sum of the two numbers will be a multiple of $4$ is

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