If $m$ rupee coins and $n$ ten paise coins are placed in a line, then the probability that the extreme coins are ten paise coins is

  • A

    $^{m + n}{C_m}/{n^m}$

  • B

    $\frac{{n\,(n - 1)}}{{(m + n)\,(m + n - 1)}}$

  • C

    $^{m + n}{P_m}/{m^n}$

  • D

    $^{m + n}{P_n}/{n^m}$

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