If $P(A) = 0.25,\,\,P(B) = 0.50$ and $P(A \cap B) = 0.14,$ then $P(A \cap \bar B)$ is equal to
$0.61$
$0.39$
$0.48$
None of these
(d) $P(A \cap \bar B) = P(A) – P(A \cap B) = 0.25 – 0.14 = 0.11$.
$A$ and $B$ are events such that $P(A)=0.42$, $P(B)=0.48$ and $P(A$ and $B)=0.16 .$ Determine $P (A$ or $B).$
A card is drawn from a pack of cards. Find the probability that the card will be a queen or a heart
If $A$ and $B$ are two independent events, then $A$ and $\bar B$ are
Probability of solving specific problem independently by $A$ and $B$ are $\frac{1}{2}$ and $\frac{1}{3}$ respectively. If both try to solve the problem independently, find the probability that the problem is solved.
Let $S=\{1,2,3, \ldots, 2022\}$. Then the probability, that a randomly chosen number $n$ from the set $S$ such that $\operatorname{HCF}( n , 2022)=1$, is.
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