Gujarati
14.Probability
easy

यदि $P(A) = 0.25,\,\,P(B) = 0.50$ तथा $P(A \cap B) = 0.14,$ तब $P(A \cap \bar B)  =$

A

$0.61$

B

$0.39$

C

$0.48$

D

इनमें से कोई नहीं

Solution

(d) $P(A \cap \bar B) = P(A) – P(A \cap B) = 0.25 – 0.14 = 0.11$.

Standard 11
Mathematics

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