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14.Probability
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The probability that $A$ speaks truth is $\frac{4}{5}$, while this probability for $B$ is $\frac{3}{4}$. The probability that they contradict each other when asked to speak on a fact
A
$\frac{4}{5}$
B
$\frac{1}{5}$
C
$\frac{7}{{20}}$
D
$\frac{3}{{20}}$
(AIEEE-2004) (IIT-1975)
Solution
(c) Here $P(A) = \frac{3}{4},\,P(B) = \frac{4}{5}$
$\therefore $ Required probability $ = P(A).P(\bar B) + P(\bar A)\,.\,P(B) = \frac{7}{{20}}$.
Standard 11
Mathematics
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