If $A$ and $B$ are events such that $P(A \cup B) = 3/4,$ $P(A \cap B) = 1/4,$ $P(\bar A) = 2/3,$ then $P(\bar A \cap B)$ is
If $A$ and $B$ are events such that $P(A \cup B) = 3/4,$ $P(A \cap B) = 1/4,$ $P(\bar A) = 2/3,$ then $P(\bar A \cap B)$ is
- [AIEEE 2002]
- A
$\frac{5}{{12}}$
- B
$\frac{3}{8}$
- C
$\frac{5}{8}$
- D
$\frac{1}{4}$
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