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13.Statistics
normal
If $v$ is the variance and $\sigma$ is the standard deviation, then
A
$v = {\sigma ^2}$
B
${v^2} = \sigma $
C
$v = \frac{1}{\sigma }$
D
$v = \frac{1}{{{\sigma ^2}}}$
Solution
$\Rightarrow$ The standard deviation is the square root of the variance.
$\Rightarrow$ The standard deviation is expressed in the same units as the mean is, whereas the variance is expressed in squared units.
$\therefore$ If $v$ is the varimce and $\sigma$ is the standard deviation then, $v ^2=\sigma$.
Hence, this is the answer.
Standard 11
Mathematics
Similar Questions
The variance $\sigma^2$ of the data is $ . . . . . .$
$x_i$ | $0$ | $1$ | $5$ | $6$ | $10$ | $12$ | $17$ |
$f_i$ | $3$ | $2$ | $3$ | $2$ | $6$ | $3$ | $3$ |
Find the standard deviation for the following data:
${x_i}$ | $3$ | $8$ | $13$ | $18$ | $25$ |
${f_i}$ | $7$ | $10$ | $15$ | $10$ | $6$ |
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