If $v$ is the variance and $\sigma$ is the standard deviation, then
$v = {\sigma ^2}$
${v^2} = \sigma $
$v = \frac{1}{\sigma }$
$v = \frac{1}{{{\sigma ^2}}}$
Find the standard deviation of the first n natural numbers.
For the frequency distribution :
Variate $( x )$ | $x _{1}$ | $x _{1}$ | $x _{3} \ldots \ldots x _{15}$ |
Frequency $(f)$ | $f _{1}$ | $f _{1}$ | $f _{3} \ldots f _{15}$ |
where $0< x _{1}< x _{2}< x _{3}<\ldots .< x _{15}=10$ and
$\sum \limits_{i=1}^{15} f_{i}>0,$ the standard deviation cannot be
If the variance of the first $n$ natural numbers is $10$ and the variance of the first m even natural numbers is $16$, then $m + n$ is equal to
The variance of first $50$ even natural numbers is
The variance of $20$ observation is $5$ . If each observation is multiplied by $2$ , then the new variance of the resulting observations, is