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13.Statistics
normal
यदि प्रसरण $v$ तथा मानक विचलन है, तब
A
$v = {\sigma ^2}$
B
${v^2} = \sigma $
C
$v = \frac{1}{\sigma }$
D
$v = \frac{1}{{{\sigma ^2}}}$
Solution
$\Rightarrow$ The standard deviation is the square root of the variance.
$\Rightarrow$ The standard deviation is expressed in the same units as the mean is, whereas the variance is expressed in squared units.
$\therefore$ If $v$ is the varimce and $\sigma$ is the standard deviation then, $v ^2=\sigma$.
Hence, this is the answer.
Standard 11
Mathematics