13.Statistics
hard

The outcome of each of $30$ items was observed; $10$ items gave an outcome $\frac{1}{2} - d$ each, $10$ items gave outcome $\frac {1}{2}$ each and the remaining $10$ items gave outcome $\frac{1}{2} + d$ each. If the variance of this outcome data is $\frac {4}{3}$ then $\left| d \right|$ equals

A

$\frac {2}{3}$

B

$2$

C

$\frac {\sqrt 5}{2}$

D

$\sqrt 2$

(JEE MAIN-2019)

Solution

Variance remains some if same number is subracted from  each observation. (subtract $10$ from each observation)

$\therefore \frac{{1{{\left( { – d} \right)}^2} + 10{{\left( 0 \right)}^2} + 10{{\left( d \right)}^2}}}{{30}} – {\left( {\frac{{10\left( { – d} \right) + 10\left( 0 \right) + 10\left( d \right)}}{{30}}} \right)^2} = \frac{4}{3}$

$\frac{{20{d^2}}}{{30}} = \frac{4}{3}$

$ \Rightarrow {d^2} = 2$

$\left( d \right) = \sqrt 2 $

Standard 11
Mathematics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.