If (p wedge ∼ r) ⇒ (q vee r) is false and q and r are both false, then p is

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Mathematical Reasoning

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If $(p\; \wedge \sim r) \Rightarrow (q \vee r)$ is false and $q$ and $r$ are both false, then $p$ is

A

true

B

false

C

May be true or false

D

Data insufficient

Solution

(a) Given result means $p\; \wedge \sim r$ is true, $q \vee r$ is false.

Standard 11

Mathematics

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