- Home
- Standard 11
- Mathematics
Mathematical Reasoning
medium
$\sim (p \Rightarrow q) \Leftrightarrow \sim p\; \vee \sim q$ is
A
A tautology
B
A contradiction
C
Neither a tautology nor a contradiction
D
Cannot come to any conclusion
Solution
(c) Last column shows that result is neither a tautology nor a contradiction.
|
$p$ |
$q$ |
$p⇒q$ |
$~(p⇒q)$ |
$~p$ |
$~q$ |
$~p \vee ~q$ |
$~(p⇒q)$ ⇔ $~p \vee ~q$ |
|
$T$ |
$T$ |
$T$ |
$F$ |
$F$ |
$F$ |
$F$ |
$T$ |
|
$T$ |
$F$ |
$F$ |
$T$ |
$F$ |
$T$ |
$T$ |
$T$ |
|
$F$ |
$T$ |
$T$ |
$F$ |
$T$ |
$F$ |
$T$ |
$F$ |
|
$F$ |
$F$ |
$T$ |
$F$ |
$T$ |
$T$ |
$T$ |
$F$ |
Standard 11
Mathematics
