sim (p Rightarrow q) Leftrightarrow sim p; ve | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(c) Last column shows that result is neither a tautology nor a contradiction.


	
		
			
			$p$
			
			
			$q$
			
			
			$p&rArr;q$

Vedclass · Accepted Answer

Neither a tautology nor a contradiction

Vedclass · Answer

(c) Last column shows that result is neither a tautology nor a contradiction.


	
		
			
			$p$
			
			
			$q$
			
			
			$p&rArr;q$
			
			
			$~(p&rArr;q)$
			
			
			$~p$
			
			
			$~q$
			
			
			$~p \vee ~q$
			
			
			$~(p&rArr;q)$

			&hArr; $~p \vee ~q$
			
		
		
			
			$T$
			
			
			$T$
			
			
			$T$
			
			
			$F$
			
			
			$F$
			
			
			$F$
			
			
			$F$
			
			
			$T$
			
		
		
			
			$T$
			
			
			$F$
			
			
			$F$
			
			
			$T$
			
			
			$F$
			
			
			$T$
			
			
			$T$
			
			
			$T$
			
		
		
			
			$F$
			
			
			$T$
			
			
			$T$
			
			
			$F$
			
			
			$T$
			
			
			$F$
			
			
			$T$
			
			
			$F$
			
		
		
			
			$F$
			
			
			$F$
			
			
			$T$
			
			
			$F$
			
			
			$T$
			
			
			$T$
			
			
			$T$
			
			
			$F$

$\sim (p \Rightarrow q) \Leftrightarrow \sim p\; \vee \sim q$ is

Similar Questions

The negation of the statement $(( A \wedge( B \vee C )) \Rightarrow( A \vee B )) \Rightarrow A$ is

The number of values of $r \in\{p, q, \sim p , \sim q \}$ for which $((p \wedge q) \Rightarrow(r \vee q)) \wedge((p \wedge r) \Rightarrow q)$ is a tautology, is:

The number of ordered triplets of the truth values of $p, q$ and $r$ such that the truth value of the statement $(p \vee q) \wedge(p \vee r) \Rightarrow(q \vee r)$ is True, is equal to

Negation of $(p \Rightarrow q) \Rightarrow(q \Rightarrow p)$ is

The negation of the expression $q \vee((\sim q) \wedge p)$ is equivalent to