sim (p Rightarrow q) Leftrightarrow sim p; ve | vedclass

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Question

(c) Last column shows that result is neither a tautology nor a contradiction.


	
		
			
			$p$
			
			
			$q$
			
			
			$p&rArr;q$

Vedclass · Accepted Answer

Neither a tautology nor a contradiction

Vedclass · Answer

(c) Last column shows that result is neither a tautology nor a contradiction.


	
		
			
			$p$
			
			
			$q$
			
			
			$p&rArr;q$
			
			
			$~(p&rArr;q)$
			
			
			$~p$
			
			
			$~q$
			
			
			$~p \vee ~q$
			
			
			$~(p&rArr;q)$

			&hArr; $~p \vee ~q$
			
		
		
			
			$T$
			
			
			$T$
			
			
			$T$
			
			
			$F$
			
			
			$F$
			
			
			$F$
			
			
			$F$
			
			
			$T$
			
		
		
			
			$T$
			
			
			$F$
			
			
			$F$
			
			
			$T$
			
			
			$F$
			
			
			$T$
			
			
			$T$
			
			
			$T$
			
		
		
			
			$F$
			
			
			$T$
			
			
			$T$
			
			
			$F$
			
			
			$T$
			
			
			$F$
			
			
			$T$
			
			
			$F$
			
		
		
			
			$F$
			
			
			$F$
			
			
			$T$
			
			
			$F$
			
			
			$T$
			
			
			$T$
			
			
			$T$
			
			
			$F$

$\sim (p \Rightarrow q) \Leftrightarrow \sim p\; \vee \sim q$ is

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