If $p, q, r$ are simple propositions, then $(p \wedge q) \wedge (q \wedge r)$ is true then
If $p, q, r$ are simple propositions, then $(p \wedge q) \wedge (q \wedge r)$ is true then
- A
$p, q, r$ are all false
- B
$p, q, r$ are all true
- C
$p, q$ are true and $r$ is false
- D
$p$ is true and $q$ and $r$ are false
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