If p, q, r are simple propositions, then (p wedge q) wedge (q wedge r) is true then

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Mathematical Reasoning

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If $p, q, r$ are simple propositions, then $(p \wedge q) \wedge (q \wedge r)$ is true then

A

$p, q, r$ are all false

B

$p, q, r$ are all true

C

$p, q$ are true and $r$ is false

D

$p$ is true and $q$ and $r$ are false

Solution

(b) $(p \wedge q) \wedge (q \wedge r)$ is true means $p \wedge q$, $q \wedge r$ are both true.

==> $p, q, r$ are all true.

Standard 11

Mathematics

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