If $p \Rightarrow (\sim p \vee q)$ is false, the truth values of $p$ and $q$ are respectively
$F, T$
$F, F$
$T, T$
$T, F$
The negation of the compound proposition $p \vee (\sim p \vee q)$ is
If the truth value of the Boolean expression $((\mathrm{p} \vee \mathrm{q}) \wedge(\mathrm{q} \rightarrow \mathrm{r}) \wedge(\sim \mathrm{r})) \rightarrow(\mathrm{p} \wedge \mathrm{q}) \quad$ is false then the truth values of the statements $\mathrm{p}, \mathrm{q}, \mathrm{r}$ respectively can be:
The statement $A \rightarrow( B \rightarrow A )$ is equivalent to
If $p , q$ and $r$ are three propositions, then which of the following combination of truth values of $p , q$ and $r$ makes the logical expression $\{(p \vee q) \wedge((\sim p) \vee r)\} \rightarrow((\sim q) \vee r)$ false ?
The negation of $ \sim s \vee \left( { \sim r \wedge s} \right)$ is equivalent to :