If E is electric field intensity of an electrostatic field, then electrostatic energy density is pro

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2. Electric Potential and Capacitance

easy

If $E$ is the electric field intensity of an electrostatic field, then the electrostatic energy density is proportional to

A

$E$

B

${E^2}$

C

$1/{E^2}$

D

${E^3}$

Solution

(b) Electrostatic energy density $\frac{{dU}}{{dV}} = \frac{1}{2}K{\varepsilon _0}{E^2}$
$\frac{{dU}}{{dV}} \propto {E^2}$

Standard 12

Physics

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