If n(A) = 3 and n(B) = 6 and A subseteq B . Then number of elements in A cap B is equal to

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1.Set Theory

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If $n(A) = 3$ and $n(B) = 6$ and $A \subseteq B$. Then the number of elements in $A \cap B$ is equal to

A

$3$

B

$9$

C

$6$

D

None of these

Solution

(a) Since $A \subseteq B,$ $\therefore$ $A \cap B = A$
$\therefore$ $n\,(A \cap B) = n(A) = 3$.

Standard 11

Mathematics

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