If sets A and B are defined as A = { (x,,y):y = {e^x},,x ∈ R} ; B = { (x,,y):y = x,,x ∈ R} , the

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1.Set Theory

easy

If the sets $A$ and $B$ are defined as $A = \{ (x,\,y):y = {e^x},\,x \in R\} $; $B = \{ (x,\,y):y = x,\,x \in R\} ,$ then

A

$B \subseteq A$

B

$A \subseteq B$

C

$A \cap B = \phi $

D

$A \cup B = A$

Solution

(c) Since, $y = {e^x}$ and $y = x$ do not meet for any $x \in R$

$\therefore A \cap B = \phi $.

Standard 11

Mathematics

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