If $W$ be the weight of a body of density $\rho $ in vacuum then its apparent weight in air of density $\sigma $ is
$\frac{{W\rho }}{\sigma }$
$W\,\left( {\frac{\rho }{\sigma } - 1} \right)$
$\frac{W}{\rho }\sigma $
$W\,\left( {1 - \frac{\sigma }{\rho }} \right)$
A body remain in equilibrium at which depth of liquid ? Explain ?
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