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9-1.Fluid Mechanics
easy
If $W$ be the weight of a body of density $\rho $ in vacuum then its apparent weight in air of density $\sigma $ is
A
$\frac{{W\rho }}{\sigma }$
B
$W\,\left( {\frac{\rho }{\sigma } - 1} \right)$
C
$\frac{W}{\rho }\sigma $
D
$W\,\left( {1 - \frac{\sigma }{\rho }} \right)$
Solution
(d) Apparent weight in air $= W -$ upthrust = $V\rho g – V\sigma g$
=$V\rho g\left( {1 – \frac{\sigma }{\rho }} \right)$= $W\left( {1 – \frac{\sigma }{\rho }} \right)$
Standard 11
Physics
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