Gujarati
Hindi
3 and 4 .Determinants and Matrices
normal

If $px^4 + qx^3 + rx^2 + sx + t$ $\equiv$ $\left| {\begin{array}{*{20}{c}}{{x^2}\, + \,\,3x}&{x\, - \,1}&{x\, + \,3}\\{x\, + \,1}&{2\, - \,x}&{x\, - \,3}\\{x\, - \,3}&{x\, + \,4}&{3x}\end{array}} \right|$ then $t =$

A

$33$

B

$0$

C

$21$

D

none

Solution

Put $x = 0 \, \&$ then evaluate

Standard 12
Mathematics

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