If P = (1, 0) ; Q = (-1, 0) ,,ane,, R = (2, 0 | vedclass

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Question

Let $S(x, y)$ and $P(1,0), Q(-1,0), R(2,0)$ are given points

$	herefore(S Q)^{2}+(S R)^{2}=2(S P)^{2}$

$\Rightarrow(x+1)^{2}+y^{2}+(x-2)^{2}+y^

Vedclass · Accepted Answer

a straight line parallel to $y-$ axis .

Vedclass · Answer

Let $S(x, y)$ and $P(1,0), Q(-1,0), R(2,0)$ are given points

$	herefore(S Q)^{2}+(S R)^{2}=2(S P)^{2}$

$\Rightarrow(x+1)^{2}+y^{2}+(x-2)^{2}+y^{2}=2\left[(x-1)^{2}+y^{2}ight]$

$\Rightarrow 2 x^{2}+2 y^{2}+2 x-4 x+5=2 x^{2}+2 y^{2}-4 x+2$

$\Rightarrow 2 x+3=0$

which is a straight line parallel to $y$ -axis.

If $P = (1, 0) ; Q = (-1, 0) \,\,ane\,\, R = (2, 0)$ are three given points, then the locus of the points $S$ satisfying the relation, $SQ^2 + SR^2 = 2 SP^2$ is :

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