Two sides of a parallelogram are along lines, x + y = 3 and x -y + 3 = 0 . If its diagonals intersec

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9.Straight Line

hard

Two sides of a parallelogram are along the lines, $x + y = 3$ and $x -y + 3 = 0$. If its diagonals intersect at $(2, 4)$, then one of its vertex is

A

$(3, 5)$

B

$(2, 1)$

C

$(2, 6)$

D

$(3, 6)$

(JEE MAIN-2019)

Solution

Intersection point is $A(0,3)$

$M=(4,6)$

$B \Rightarrow \left( {1,2} \right),D \to \left( {3,6} \right)$

Standard 11

Mathematics

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