3 and 4 .Determinants and Matrices
normal

જો $q_1$ , $q_2$ , $q_3$ એ સમીકરણ $x^3 + 64$ = $0$ ના બીજ હોય તો $\left| {\begin{array}{*{20}{c}}
  {{q_1}}&{{q_2}}&{{q_3}} \\ 
  {{q_2}}&{{q_3}}&{{q_1}} \\ 
  {{q_3}}&{{q_1}}&{{q_2}} 
\end{array}} \right|$ ની કિમંત મેળવો.

A

$1$

B

$4$

C

$16$

D

$0$

Solution

$\left|\begin{array}{lll}{\mathrm{q}_{1}} & {\mathrm{q}_{2}} & {\mathrm{q}_{3}} \\ {\mathrm{q}_{2}} & {\mathrm{q}_{3}} & {\mathrm{q}_{1}} \\ {\mathrm{q}_{3}} & {\mathrm{q}_{1}} & {\mathrm{q}_{2}}\end{array}\right| \rightarrow \mathrm{C}_{1}+\mathrm{C}_{2}+\mathrm{C}_{3}$

$=\left(\mathrm{q}_{1}+\mathrm{q}_{2}+\mathrm{q}_{3}\right)\left|\begin{array}{lll}{1} & {\mathrm{q}_{2}} & {\mathrm{q}_{3}} \\ {1} & {\mathrm{q}_{3}} & {\mathrm{q}_{1}} \\ {1} & {\mathrm{q}_{1}} & {\mathrm{q}_{2}}\end{array}\right|$

$=0$   ($\because$ sum of roots is zero)

Standard 12
Mathematics

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