If alpha, beta,gamma are positive number such | vedclass

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Question

$\beta+\gamma=\alpha$

$\frac{	an \beta+	an \gamma}{1-	an \beta 	an \gamma}=	an \alpha$

$	an \beta+	an \gamma=	an \alpha-	an \beta 	an

Vedclass · Accepted Answer

$ - \sqrt {\frac{{2	an \beta  + 	an \gamma }}{{	an \gamma }}}$

Vedclass · Answer

$\beta+\gamma=\alpha$

$\frac{	an \beta+	an \gamma}{1-	an \beta 	an \gamma}=	an \alpha$

$	an \beta+	an \gamma=	an \alpha-	an \beta 	an \gamma 	an \alpha$

use $\alpha+\beta=\pi \,\,\,and\,\,\,\,\,$$ \beta+r= \alpha$

$	an \beta+	an \gamma=-	an \beta+	an ^{2} \alpha 	an \gamma$

$	an ^{2} \alpha=\frac{2 	an \beta+	an \gamma}{	an \gamma}$

$	an \alpha=-\sqrt{\frac{2 	an \beta+	an \gamma}{	an \gamma}}$

If $\alpha$, $\beta$,$\gamma$ are positive number such that $\alpha + \beta = \pi$ and $\beta + \gamma = \alpha$, then $tan\ \alpha$ is equal to - (where $\gamma \ne n\pi ,n \in I$ )

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