If $h\left( x \right) = \left[ {\ln \frac{x}{e}} \right] + \left[ {\ln \frac{e}{x}} \right]$ ,where [.] denotes greatest integer function, then which of the following is false ?
Range of $h(x)$ is $\{-1, 0\}$
$h(x)$ is a periodic function
If $h(x) = -1$ , then $x$ can be rational as well as irrational
If $h(x) = 0$ , then $x$ must be irrational
Let $f(x)=\frac{x-1}{x+1}, x \in R-\{0,-1,1)$. If $f^{a+1}(x)=f\left(f^{n}(x)\right)$ for all $n \in N$, then $f^{\prime}(6)+f(7)$ is equal to
Domain of the function $f(x)\,=\,\frac{1}{{\sqrt {(x + 1)({e^x} - 1)(x - 4)(x + 5)(x - 6)} }}$
The range of the function $f(x){ = ^{7 - x}}{\kern 1pt} {P_{x - 3}}$ is
If $y = f(x) = \frac{{ax + b}}{{cx - a}}$, then $x$ is equal to
$f : R \to R$ is defined as
$f(x) = \left\{ {\begin{array}{*{20}{c}}
{{x^2} + 2mx - 1\,,}&{x \leq 0}\\
{mx - 1\,\,\,\,\,\,\,\,\,\,\,\,\,,}&{x > 0}
\end{array}} \right.$
If $f (x)$ is one-one then the set of values of $'m'$ is