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If $\overrightarrow A = 3\hat i + \hat j + 2\hat k$ and $\overrightarrow B = 2\hat i - 2\hat j + 4\hat k$ then value of $|\overrightarrow A \times \overrightarrow B |\,$ will be
$8\sqrt 2 $
$8\sqrt 3 $
$8\sqrt 5 $
$5\sqrt 8 $
Solution
(b) $\overrightarrow A \, \times \,\overrightarrow B \, = \left|{\,\begin{array}{*{20}{c}}{\hat i\,\,}&{\hat j\,\,}&{\hat k}\\{3\,\,}&{1\,\,}&2\\{2\,\,\,}&{ – 2\,\,\,}&4\end{array}\,} \right|\,$
$ = (1 \times 4 – 2 \times – 2)\hat i + (2 \times 2 – 4 \times 3)\hat j + (3 \times – 2 – 1 \times 2)\hat k$
$ = 8\hat i – 8\hat j – 8\hat k$
$\therefore$ Magnitude of $\overrightarrow {\rm{A}} \, \times \overrightarrow {\rm{B}} \, = ,|\overrightarrow {\rm{A}} \times \overrightarrow {\rm{B}} |\, = \sqrt {{{(8)}^2} + {{( – 8)}^2} + {{( – 8)}^2}} \,$
$ = 8\sqrt 3 $