If a bimetallic strip is heated, it will
Bend towards the metal with lower linear thermal expansion coefficient
Bend towards the metal with higher linear thermal expansion coefficient
Not bend at all
None
A simple pendulum made of a bob of mass $m$ and a metallic wire of negligible mass has time period $2s$ at $T = 0\,^oC$ . If the temeprature of the wire is increased and the corresponding change in its time peirod is plotted against its temperature, the resulting graph is a line of slope $S$. If the coefficient of linear expansion of metal is $\alpha $ then the value of $S$ is
A beaker of height $H$ is made up of a material whose coefficient of linear thermal expansion is $3\alpha $ . It is filled up to the brim by a liquid whose coefficient of thermal expansion is $\alpha $. If now the beaker along with its contents is uniformly heated through a small temperature $T$ the level of liquid will reduce by (given $\alpha << 1$)
Two conducting cylinders of equal length but different radii are connected in series between two heat baths kept at temperatures $T _1=300 K$ and $T _2=100 K$, as shown in the figure. The radius of the bigger cylinder is twice that of the smaller one and the thermal conductivities of the materials of the smaller and the larger cylinders are $K _1$ and $K _2$ respectively. If the temperature at the junction of the two cylinders in the steady state is $200 K$, then $K _1 / K _2=$ . . . . .
Density of substance at $0°C$ is $10\, gm/cc$ and at $100°C,$ its density is $9.7\, gm/cc$. The coefficient of linear expansion of the substance will be
$Assertion :$ In pressure-temperature $(P-T)$ phase diagram of water, the slope of the melting curve is found to be negative.
$Reason :$ Ice contracts on melting to water.