8.Electromagnetic waves
easy

શૂન્યાવકાશમાં વિદ્યુતચુંબકીય તરંગને $E_y=E_0 \sin (k x-\omega t)$; થી અપાય છે તથા $B_z=B_0 \sin (k x-\omega t)$, તો 

A

$E_0 k=B_0 \omega$

B

$E_0 B_0=\omega k$

C

$E_0 \omega=B_0 k$

D

$E_0 B_0=\frac{\omega}{k}$

Solution

(a)

Speed of wave $=\frac{E_0}{B_0}=\frac{\omega}{k}$

$\therefore k E_0=\omega B_0$

Standard 12
Physics

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