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8.Electromagnetic waves
easy
શૂન્યાવકાશમાં વિદ્યુતચુંબકીય તરંગને $E_y=E_0 \sin (k x-\omega t)$; થી અપાય છે તથા $B_z=B_0 \sin (k x-\omega t)$, તો
A
$E_0 k=B_0 \omega$
B
$E_0 B_0=\omega k$
C
$E_0 \omega=B_0 k$
D
$E_0 B_0=\frac{\omega}{k}$
Solution
(a)
Speed of wave $=\frac{E_0}{B_0}=\frac{\omega}{k}$
$\therefore k E_0=\omega B_0$
Standard 12
Physics