If an unbiased die, marked with -2,-1,0,1,2,3 | vedclass

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Question

Either all outcomes are positive or any two are negative.

$	ext { Now, } p = P 	ext { (positive) }=\frac{3}{6}=\frac{1}{2}$

$q = p 	ext { (ne

Vedclass · Accepted Answer

$\frac{521}{2592}$

Vedclass · Answer

Either all outcomes are positive or any two are negative.

$	ext { Now, } p = P 	ext { (positive) }=\frac{3}{6}=\frac{1}{2}$

$q = p 	ext { (negative })=\frac{2}{6}=\frac{1}{3}$

Required probability

$={ }^5 C_5\left(\frac{1}{2}ight)^5+{ }^5 C_2\left(\frac{1}{3}ight)^2\left(\frac{1}{2}ight)^3+{ }^5 C_4\left(\frac{1}{3}ight)^4\left(\frac{1}{2}ight)^1$

$=\frac{521}{2592}$

If an unbiased die, marked with $-2,-1,0,1,2,3$ on its faces, is through five times, then the probability that the product of the outcomes is positive, is :

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