If diagonals of a parallelogram are $\left( {5\hat i - 4\hat j + 3\hat k} \right)$ and $\left( {3\hat i + 2\hat j - \hat k} \right)$ then its area is
$\sqrt {171} \,unit$
$\sqrt {72} \,unit$
$171\,unit$
$72\,unit$
colum $I$ | colum $II$ |
$(A)$ $A \cdot B =| A \times B |$ | $(p)$ $\theta=90^{\circ}$ |
$(B)$ $A \cdot B = B ^2$ | $(q)$ $\theta=0^{\circ}$ or $180^{\circ}$ |
$(C)$ $|A+B|=|A-B|$ | $(r)$ $A=B$ |
$(D)$ $|A \times B|=A B$ | $(s)$ None |
The area of the parallelogram represented by the vectors $\overrightarrow A = 2\hat i + 3\hat j$ and $\overrightarrow B = \hat i + 4\hat j$ is.......$units$
For any two vectors $\overrightarrow A $ and $\overrightarrow B $, if $\overrightarrow A \,.\,\overrightarrow B = \,\,|\overrightarrow A \times \overrightarrow B |,$ the magnitude of $\overrightarrow C = \overrightarrow A + \overrightarrow B $ is equal to