If dimensions of critical velocity $v_c$ of a liquid flowing through a tube are expressed as$ [\eta ^x \rho ^yr^z]$ where $\eta ,\rho $ and $r $ are the coefficient of viscosity of liquid, density of liquid and radius of the tube respectively, then the values of $x, y$ and $z$ are given by
$1,1,1$
$1,-1,-1$
$-1,-1,1$
$-1,-1,-1$
Dimension of $\frac{1}{\mu_0 \varepsilon_0}$ should be equal to
If Surface tension $(S)$, Moment of Inertia $(I)$ and Planck’s constant $(h)$, were to be taken as the fundamental units, the dimensional formula for linear momentum would be
The dimensions of ${\left( {{\mu _0}{\varepsilon _0}} \right)^{ - \frac{1}{2}}}$ are
If $C$ and $V$ represent capacity and voltage respectively then what are the dimensions of $\lambda,$ where $\frac{ C }{ V }=\lambda ?$
Dimensional formula for volume elasticity is