If force F , velocity V and time T are taken as fundamental units then dimension of force in pressur

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1.Units, Dimensions and Measurement

medium

If force $F$ , velocity $V$ and time $T$ are taken as fundamental units then dimension of force in the pressure is

$3$

$5$

$6$

$1$

Solution

$[\text { Pressure }]$

$=\left[\frac{\text { Force }}{\text { Area }}\right]=\left[\frac{\mathrm{F}}{(\mathrm{VT})^{2}}\right]=\left[\mathrm{F}^{1} \mathrm{V}^{-2} \mathrm{T}^{-2}\right]$

Standard 11

Physics

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hard

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(JEE MAIN-2015)

If force $F$ , velocity $V$ and time $T$ are taken as fundamental units then dimension of force in the pressure is

Solution

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