If speed V, area A and force F are chosen as | vedclass

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Question

$Y = F ^{ x } A ^{ y } V ^{z}$

$M ^{1} L ^{-1} T ^{-2}=\left[ MLT ^{-2}\right] x \left[ L ^{2}\right] y \left[ L T ^{-1}\right]^{z}$

$M ^{1} L ^

Vedclass · Accepted Answer

$FA ^{-1} V ^{0}$

Vedclass · Answer

$Y = F ^{ x } A ^{ y } V ^{z}$

$M ^{1} L ^{-1} T ^{-2}=\left[ MLT ^{-2}\right] x \left[ L ^{2}\right] y \left[ L T ^{-1}\right]^{z}$

$M ^{1} L ^{1} T ^{-2}=[ M ]^{ x }[ L ]^{ x +2 y +z}[ T ]^{-2 x - z }$

comparing power of $ML$ and $T$

$x=1 \ldots(1)$

$x+2 y+z=-1$$...(2)$

$-2 x-z=-2$$...(3)$

after solving

$x=1$

$y=-1$

$z=0$

$Y=F A^{-1} V^{0}$

List I	List II
$(i)$ Curie	$(A)$ $ML{T^{ - 2}}$
$(ii)$ Light year	$(B)$ $M$
$(iii)$ Dielectric strength	$(C)$ Dimensionless
$(iv)$ Atomic weight	$(D)$ $T$
$(v)$ Decibel	$(E)$ $M{L^2}{T^{ - 2}}$
	$(F)$ $M{T^{ - 3}}$
	$(G)$ ${T^{ - 1}}$
	$(H)$ $L$
	$(I)$ $ML{T^{ - 3}}{I^{ - 1}}$
	$(J)$ $L{T^{ - 1}}$

If speed $V,$ area $A$ and force $F$ are chosen as fundamental units, then the dimension of Young's modulus will be :

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