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5. Continuity and Differentiation
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If from mean value theorem, $f'({x_1}) = {{f(b) - f(a)} \over {b - a}}$, then
A
$a < {x_1} \le b$
B
$a \le {x_1} < b$
C
$a < {x_1} < b$
D
$a \le {x_1} \le b$
Solution
(c) According to mean value theorem,
In interval $[a, b]$ for $ f (x)$
$\frac{{f(b) – f(a)}}{{b – a}} = f'(c)$, where $a < c < b$
$\therefore a < {x_1} < b$.
Standard 12
Mathematics