5. Continuity and Differentiation
normal

If from mean value theorem, $f'({x_1}) = {{f(b) - f(a)} \over {b - a}}$, then

A

$a < {x_1} \le b$

B

$a \le {x_1} < b$

C

$a < {x_1} < b$

D

$a \le {x_1} \le b$

Solution

(c) According to mean value theorem,

In interval $[a, b]$ for $ f (x)$

$\frac{{f(b) – f(a)}}{{b – a}} = f'(c)$, where $a < c < b$

$\therefore a < {x_1} < b$.

Standard 12
Mathematics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.