Gujarati
13.Nuclei
easy

यदि किसी रेडियोएक्टिव तत्व की अर्द्धआयु $3$ घण्टे है, तो $9$ घण्टों के बाद इसकी सक्रियता हो जायेगी

A

$1/9$

B

$1/27$

C

$1/6$

D

$1/8$

Solution

$A = {A_0}{\left( {\frac{1}{2}} \right)^{\frac{t}{{{T_{1/2}}}}}}$ 

$\Rightarrow$ $\frac{A}{{{A_0}}} = {\left( {\frac{1}{2}} \right)^{9/3}} = \frac{1}{8}$

Standard 12
Physics

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