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9.Straight Line
hard
If in a parallelogram $ABDC$, the coordinates of $A, B$ and $C$ are respectively $(1, 2), (3, 4)$ and $(2, 5)$, then the equation of the diagonal $AD$ is
A
$5x - 3y +1 = 0$
B
$5x + 3y -11 = 0$
C
$3x - 5y + 7 = 0$
D
$3x + 5y -13 = 0$
(JEE MAIN-2019)
Solution

$E$ is $\left( {\frac{5}{2},\frac{9}{2}} \right)$
Slope of $AD = \frac{5}{3}$
Equation of $AD$ is $y – 2 = \frac{5}{3}\left( {x – 1} \right)$
$ \Rightarrow 5x – 3y + 1 = 0$
Standard 11
Mathematics