4-2.Friction
medium

यदि गुटके $A$ का द्रव्यमान $ = 10\,\,kg$, स्थैतिक घर्षण गुणांक $= 0.2$, गतिक घर्षण गुणांक $= 0.2$  हो, तो गति प्रारम्भ करने के लिए गुटके $B$ का द्रव्यमान होगा

A$2 \,kg$
B$2.2 \,kg$
C$4.8 \,kg$
D$200\, gm$

Solution

$ma = T -\mu_s mg$
friction is static as we require limiting condition. for limiting case $a=0$
$T = m_B g$
$T = \mu _{ s } \times m_A \times g$
comparing both:
$m_B \times g = 0 .2 \times m_A \times g$
$m_B =2 kg$
Standard 11
Physics

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