1.Units, Dimensions and Measurement
hard

If Surface tension $(S)$, Moment of Inertia $(I)$ and Planck’s constant $(h)$, were to be taken as the fundamental units, the dimensional formula for linear momentum would be

A

$S^{1 /2} I^{1 /2} h^0$

B

$S^{1 /2} I^{3 /2} h^{-1}$

C

$S^{3 /2} I^{1 /2} h^0$

D

$S^{1 /2} I^{1 /2} h^{-1}$

(JEE MAIN-2019)

Solution

$\begin{array}{l}
P = k\,{s^a}{i^b}{h^c}\\
Where\,k\,is\,{\rm{dimensionless}}\,{\rm{constant}}\\
ML{T^{ – 1}} = {\left( {M{T^{ – 2}}} \right)^a}\left( {M{L^2}} \right){\left( {M{L^2}{T^{ – 1}}} \right)^c}\\
a + b + c = 1\\
2b + 2c =  1\\
 – 2a – c =  – 1\\
a = \frac{1}{2}\,\,\,\,\,\,\,b = \frac{1}{2}\,\,\,\,\,\,c = 0\\
{S^{1/2}}{i^{1/2}}{h^0}
\end{array}$

Standard 11
Physics

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