If the $1011^{\text {th }}$ term from the end in the binomial expansion of $\left(\frac{4 x}{5}-\frac{5}{2 x }\right)^{2022}$ is $1024$ times $1011^{\text {th }}$ term from the beginning, then $|x|$ is equal to

  • [JEE MAIN 2023]
  • A

    $12$

  • B

    $8$

  • C

    $\frac{5}{16}$

  • D

    $15$

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