If the ${n^{th}}$ term of an $A.P.$ be $(2n - 1)$, then the sum of its first $n$ terms will be
If the ${n^{th}}$ term of an $A.P.$ be $(2n - 1)$, then the sum of its first $n$ terms will be
- A
${n^2} - 1$
- B
${(2n - 1)^2}$
- C
${n^2}$
- D
${n^2} + 1$
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- [JEE MAIN 2020]
The sum of the series $\frac{1}{2} + \frac{1}{3} + \frac{1}{6} + ........$ to $9$ terms is
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