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2. Electric Potential and Capacitance
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If the capacity of a spherical conductor is $1$ picofarad, then its diameter, would be
A
$1.8 \times {10^{ - 3}}\,m$
B
$18 \times {10^{ - 3}}\,m$
C
$1.8 \times {10^{ - 5}}\,m$
D
$18 \times {10^{ - 7}}\,m$
Solution
(b) $C = 4\pi {\varepsilon _0}R$
$R = \frac{C}{{4\pi {\varepsilon _0}}} = 9 \times {10^9} \times {10^{ – 12}} = 9 \times {10^{ – 3}}\,m$
Diameter $= 2R = 2 \times 9 \times {10^{ – 3}}m$ = $18 \times {10^{ – 3}}\,m$
Standard 12
Physics
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