Gujarati
10-2. Parabola, Ellipse, Hyperbola
medium

If the centre, vertex and focus of a hyperbola be $(0, 0), (4, 0)$ and $(6, 0)$ respectively, then the equation of the hyperbola is

A

$4{x^2} - 5{y^2} = 8$

B

$4{x^2} - 5{y^2} = 80$

C

$5{x^2} - 4{y^2} = 80$

D

$5{x^2} - 4{y^2} = 8$

Solution

(c) Centre $(0, 0)$, vertex $(4,0)$

==> $a = 4$and focus $(6,0)$

==> $ae = 4$

==> $e = \frac{3}{2}$.

Therefore $b = 2\sqrt5$

Hence required equation is $\frac{{{x^2}}}{{16}} – \frac{{{y^2}}}{{20}} = 1$

$i.e.$, $5{x^2} – 4{y^2} = 80$.

Standard 11
Mathematics

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