The eccentricity of curve ${x^2} - {y^2} = 1$ is
$\frac{1}{2}$
$\frac{1}{{\sqrt 2 }}$
$2$
$\sqrt 2 $
(d) Since it is a rectangular hyperbola,
therefore eccentricity $e = \sqrt 2 $.
Find the equation of the hyperbola satisfying the give conditions: Foci $(0,\,\pm 13),$ the conjugate axis is of length $24.$
The eccentricity of the hyperbola can never be equal to
The minimum value of ${\left( {{x_1} – {x_2}} \right)^2} + {\left( {\sqrt {2 – x_1^2} – \frac{9}{{{x_2}}}} \right)^2}$ where ${x_1} \in \left( {0,\sqrt 2 } \right)$ and ${x_2} \in {R^ + }$.
The point $\mathrm{P}(-2 \sqrt{6}, \sqrt{3})$ lies on the hyperbola $\frac{x^{2}}{a^{2}}-\frac{y^{2}}{b^{2}}=1$ having eccentricity $\frac{\sqrt{5}}{2} .$ If the tangent and normal at $\mathrm{P}$ to the hyperbola intersect its conjugate axis at the point $\mathrm{Q}$ and $\mathrm{R}$ respectively, then $QR$ is equal to :
A hyperbola passes through the foci of the ellipse $\frac{ x ^{2}}{25}+\frac{ y ^{2}}{16}=1$ and its transverse and conjugate axes coincide with major and minor axes of the ellipse, respectively. If the product of their eccentricities in one, then the equation of the hyperbola is …… .
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