Gujarati
Hindi
2. Electric Potential and Capacitance
easy

If the distance between parallel plates of a capacitor is halved and dielectric constant is doubled then the capacitance will become

A

Half

B

Two times

C

Four times

D

Remains the same

Solution

$C=\frac{\varepsilon_{0} \varepsilon_{\mathrm{r}} A}{d}$

$C^{\prime}=\frac{\varepsilon_{0} \times 2 \varepsilon_{\mathrm{r}} \mathrm{A}}{\frac{\mathrm{d}}{2}}=4 \times \frac{\varepsilon_{0} \varepsilon_{\mathrm{r}} \mathrm{A}}{\mathrm{d}}=4 \mathrm{\,C}$

Standard 12
Physics

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