If the expression $\left( {mx - 1 + \frac{1}{x}} \right)$ is always non-negative, then the minimum value of m must be

  • A

    $ - \frac{1}{2}$

  • B

    $0$

  • C

    $\frac{1}{4}$

  • D

    $\frac{1}{2}$

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