If the product of roots of the equation {x^2} | vedclass

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Question

(b) Given equation can be written as

${x^2} - 3kx + 2{k^2} - 1 = 0$

So the product of roots is $2{k^2} - 1$.

But the product of roots is $7$.

Vedclass · Accepted Answer

$k = 2$

Vedclass · Answer

(b) Given equation can be written as

${x^2} - 3kx + 2{k^2} - 1 = 0$

So the product of roots is $2{k^2} - 1$.

But the product of roots is $7$.

Hence $2{k^2} - 1 = 7 \Rightarrow 2{k^2} = 8 \Rightarrow k = \pm 2$

But $k$ cannot be negative.

If the product of roots of the equation ${x^2} - 3kx + 2{e^{2\log k}} - 1 = 0$ is $7$, then its roots will real when

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