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1. Electric Charges and Fields
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If the net electric field at point $\mathrm{P}$ along $\mathrm{Y}$ axis is zero, then the ratio of $\left|\frac{q_2}{q_3}\right|$ is $\frac{8}{5 \sqrt{x}}$, where $\mathrm{x}=$. . . . . .

A
$2$
B
$3$
C
$5$
D
$6$
(JEE MAIN-2024)
Solution

$\frac{\mathrm{Kq}_2}{20} \cos \beta=\frac{\mathrm{Kq}_3}{25} \cos \theta$
$\frac{\mathrm{Kq}_2}{20} \frac{4}{\sqrt{20}}=\frac{\mathrm{Kq}_3}{25} \frac{4}{\sqrt{25}}$
$\frac{\mathrm{q}_2}{\mathrm{q}_3}=\frac{20}{25} \sqrt{\frac{20}{25}}=\frac{8}{5 \sqrt{\mathrm{x}}}$
$\Rightarrow \sqrt{\mathrm{x}}=\frac{8 \times 25 \sqrt{25}}{5 \times 20 \sqrt{20}}$
$\mathrm{x}=5$
Standard 12
Physics
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