If the nuclear radius of {}_{13}^{27}Al is 3. | vedclass

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Question

Nuclear radius, $R=R_{0} A^{1 / 3}$

where $R_{0}$ is a constant and $A$ is the mass number

$	herefore \quad \frac{R_{\mathrm{Al}}}{R_{\mathrm{C

Vedclass · Accepted Answer

$4.8$

Vedclass · Answer

Nuclear radius, $R=R_{0} A^{1 / 3}$

where $R_{0}$ is a constant and $A$ is the mass number

$	herefore \quad \frac{R_{\mathrm{Al}}}{R_{\mathrm{Cu}}}=\frac{(27)^{1 / 3}}{(64)^{1 / 3}}=\frac{3}{4}$

or $\quad R_{\mathrm{Cu}}=\frac{4}{3} 	imes R_{\mathrm{Al}}=\frac{4}{3} 	imes 3.6 \,fermi =4.8\,fermi$

If the nuclear radius of ${}_{13}^{27}Al$ is $3.6$ fermi the approximate nuclear radius of ${}_{}^{64}Cu$ in fermi is ..........$fm$

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