1.Units, Dimensions and Measurement
hard

If the percentage errors in measuring the length and the diameter of a wire are $0.1 \%$ each. The percentage error in measuring its resistance will be:

A

$0.2 \%$

B

$0.3 \%$

C

$0.1 \%$

D

$0.144 \%$

(JEE MAIN-2024)

Solution

$\mathrm{R}=\frac{\rho \mathrm{L}}{\pi \frac{\mathrm{d}^2}{4}}$

$\frac{\Delta \mathrm{R}}{\mathrm{R}}=\frac{\Delta \mathrm{L}}{\mathrm{L}}+\frac{2 \Delta \mathrm{d}}{\mathrm{d}}$

$\frac{\Delta \mathrm{L}}{\mathrm{L}}=0.1 \% \text { and } \frac{\Delta \mathrm{d}}{\mathrm{d}}=0.1 \%$

$\frac{\Delta \mathrm{R}}{\mathrm{R}}=0.3 \%$

Standard 11
Physics

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