If the point $\left(\alpha, \frac{7 \sqrt{3}}{3}\right)$ lies on the curve traced by the mid-points of the line segments of the lines $x$ $\cos \theta+ y \sin \theta=7, \theta \in\left(0, \frac{\pi}{2}\right)$ between the coordinates axes, then $\alpha$ is equal to

  • [JEE MAIN 2023]
  • A

    $7$

  • B

    $-7$

  • C

    $-7 \sqrt{3}$

  • D

    $7 \sqrt{3}$

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