Sides AB,BC,CD and DA of a quadrilateral are x + 2y = 3,,x = 1, x

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9.Straight Line

medium

The sides $AB,BC,CD$ and $DA$ of a quadrilateral are $x + 2y = 3,\,x = 1,$ $x - 3y = 4,\,$ $\,5x + y + 12 = 0$ respectively. The angle between diagonals $AC$ and $BD$ is ......$^o$

${45}$

${60}$

${90}$

${30}$

Solution

(c) The four vertices on solving are $A( – 3,\,3)$, $B(1,\,1),$ $C(1,\, – 1)$ and $D( – 2, – 2)$.${m_1}$= slope of $AC = – 1$, ${m_2}$= slope of $BD = 1$; ${m_1}{m_2} = – 1$.

Hence the angle between diagonals $AC$ and $BD$ is $90^\circ $.

Standard 11

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normal

The sides $AB,BC,CD$ and $DA$ of a quadrilateral are $x + 2y = 3,\,x = 1,$ $x - 3y = 4,\,$ $\,5x + y + 12 = 0$ respectively. The angle between diagonals $AC$ and $BD$ is ......$^o$

Solution

Similar Questions

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